Please don't like my thread-campaign

mromutt

Duck Army
Staff member
Oct 14, 2014
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mromutt
Yeah I've been trying to figure out...
When I times mg/l (or ppm) by MLD (million liters a day) how do I know what the end result is in kg or whatever?
Lol.
Like... I get a number but what's the units in?
Does the 1 by the 1 part per million divided by a million mean I'm in liters now?

Hahaha
good luck there XD and stop killing fictional people
 

DarthMatter

Space Marshal
Jul 18, 2016
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DarthMatter
Yeah I've been trying to figure out...
When I times mg/l (or ppm) by MLD (million liters a day) how do I know what the end result is in kg or whatever?
Lol.
Like... I get a number but what's the units in?
Does the 1 by the 1 part per million divided by a million mean I'm in liters now?

Hahaha
Easiest way to always be sure is to convert to the base SI units at the start. Then you always get another base SI unit.
How you do it in general is dimensional analysis if you wanna be academic about it. But that may be a bit too... bureaucratic in it's normal form...
How you do it the easy way is to just shove the units through the same mathematical expression you put the numbers through (or do it along with the numbers at the same time).
So mg/L * 1 000 000 * L (I'm going with big "L", easier to see in digital)
with m = 1/1000 and L/L=1 you get
g*1/1000*1 000 000 = g*1000
One thousand grams or 1 kilogram :slight_smile:
 

CrudeSasquatch

Space Marshal
Jan 1, 2016
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CrudeSasquatch
Easiest way to always be sure is to convert to the base SI units at the start. Then you always get another base SI unit.
How you do it in general is dimensional analysis if you wanna be academic about it. But that may be a bit too... bureaucratic in it's normal form...
How you do it the easy way is to just shove the units through the same mathematical expression you put the numbers through (or do it along with the numbers at the same time).
So mg/L * 1 000 000 * L (I'm going with big "L", easier to see in digital)
with m = 1/1000 and L/L=1 you get
g*1/1000*1 000 000 = g*1000
One thousand grams or 1 kilogram :slight_smile:
Ooh.
Ooh Kay.
So what you're saying is that Canatown, Canaprov, population 0, is actually going to die 100% of the time eh
 

DarthMatter

Space Marshal
Jul 18, 2016
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DarthMatter
Ooh.
Ooh Kay.
So what you're saying is that Canatown, Canaprov, population 0, is actually going to die 100% of the time eh
Maybe. Did you answer in kilograms?
Are you sure about the numbers?
 

DarthMatter

Space Marshal
Jul 18, 2016
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DarthMatter
Just take the hole value of what you are calculating and put in the equation (ex you insert 10 kg instead of the number 10) and it should work fine. You will (almost) never gain anything from skipping the units as (almost) everything you calculate has/uses units in some way.
 

DarthMatter

Space Marshal
Jul 18, 2016
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DarthMatter
Closer to engineering probably.
If I wanted to go full science I could do the dimensional analysis I mentioned :)

liter = volume = [V]
mg = 10^(-3)kg = 10^(-3) mass = 10^(-3) [M]
Day = time [t]

10^(-3) * [M] * [V]^(-1) * 10^6 * [V] * [t]^(-1) = 10^(-3) * 10^6 * [M] * [t]^(-1)

translated:

=> 10^(-3 + 6)* mass/time
=> 10^3*mass/time

or translated into common terms: kilograms per day
 

Beerjerker

Grand Admiral
Sep 8, 2015
2,205
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Beerjerker
Easiest way to always be sure is to convert to the base SI units at the start. Then you always get another base SI unit.
How you do it in general is dimensional analysis if you wanna be academic about it. But that may be a bit too... bureaucratic in it's normal form...
How you do it the easy way is to just shove the units through the same mathematical expression you put the numbers through (or do it along with the numbers at the same time).
So mg/L * 1 000 000 * L (I'm going with big "L", easier to see in digital)
with m = 1/1000 and L/L=1 you get
g*1/1000*1 000 000 = g*1000
One thousand grams or 1 kilogram :slight_smile:
Closer to engineering probably.
If I wanted to go full science I could do the dimensional analysis I mentioned :slight_smile:

liter = volume = [V]
mg = 10^(-3)kg = 10^(-3) mass = 10^(-3) [M]
Day = time [t]

10^(-3) * [M] * [V]^(-1) * 10^6 * [V] * [t]^(-1) = 10^(-3) * 10^6 * [M] * [t]^(-1)

translated:

=> 10^(-3 + 6)* mass/time
=> 10^3*mass/time

or translated into common terms: kilograms per day
844.jpg
 

DarthMatter

Space Marshal
Jul 18, 2016
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DarthMatter
It's so fun to show people outside uni these things. It's completely natural to do this and think in these terms after the first month at my education, so your worldview gets a bit... skewed... since you only hang around those at the same education or the same university :P
 

Beerjerker

Grand Admiral
Sep 8, 2015
2,205
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Beerjerker
It's so fun to show people outside uni these things. It's completely natural to do this and think in these terms after the first month at my education, so your worldview gets a bit... skewed... since you only hang around those at the same education or the same university :P
Try not to get corrupted by chaos while you are protecting us from the horrors of the warp!
download (2).jpg

Maybe that's what happened to @CrudeSasquatch when he poisoned all those fictional people? Should we summon the Inquisition?
 

Black Sunder

Rock Raiders
Officer
Jun 19, 2014
8,270
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Black_Sunder
Try not to get corrupted by chaos while you are protecting us from the horrors of the warp!
View attachment 6309
Maybe that's what happened to @CrudeSasquatch when he poisoned all those fictional people? Should we summon the Inquisition?
Montoya looks different lately.....corporate sponsorship is a bad drug to get hooked on.
 

DarthMatter

Space Marshal
Jul 18, 2016
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DarthMatter

CrudeSasquatch

Space Marshal
Jan 1, 2016
3,876
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CrudeSasquatch
Closer to engineering probably.
If I wanted to go full science I could do the dimensional analysis I mentioned :slight_smile:

liter = volume = [V]
mg = 10^(-3)kg = 10^(-3) mass = 10^(-3) [M]
Day = time [t]

10^(-3) * [M] * [V]^(-1) * 10^6 * [V] * [t]^(-1) = 10^(-3) * 10^6 * [M] * [t]^(-1)

translated:

=> 10^(-3 + 6)* mass/time
=> 10^3*mass/time

or translated into common terms: kilograms per day
So instead of MATH homework I walked toward the subwoofer explosion sounds coming from the practice artillery range and enjoyed the pleasant irresistible percussion of the maths sciences of War. Then I ate hotdogs boiled in tomato ketchup and onion soup, or as the army calls it, "gourmet sausage fiber dinner".
 

Aramil

Space Marshal
Nov 23, 2016
168
580
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Aramil_Lorrathain
Yeah I've been trying to figure out...
When I times mg/l (or ppm) by MLD (million liters a day) how do I know what the end result is in kg or whatever?
Lol.
Like... I get a number but what's the units in?
Does the 1 by the 1 part per million divided by a million mean I'm in liters now?

Hahaha
What? lol

The answer is obvious! swap the water supply for a beer supply. Who's gonna care after that?
 
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