Please don't like my thread-campaign

[mromutt]

Yeah I've been trying to figure out...
When I times mg/l (or ppm) by MLD (million liters a day) how do I know what the end result is in kg or whatever?
Lol.
Like... I get a number but what's the units in?
Does the 1 by the 1 part per million divided by a million mean I'm in liters now?

Hahaha

good luck there XD and stop killing fictional people

 

[CrudeSasquatch]

good luck there XD and stop killing fictional people

CrudeSasquatch will have to delete all of his video Games to fulfill that order

 

[DarthMatter]

Yeah I've been trying to figure out...
When I times mg/l (or ppm) by MLD (million liters a day) how do I know what the end result is in kg or whatever?
Lol.
Like... I get a number but what's the units in?
Does the 1 by the 1 part per million divided by a million mean I'm in liters now?

Hahaha

Easiest way to always be sure is to convert to the base SI units at the start. Then you always get another base SI unit.
How you do it in general is dimensional analysis if you wanna be academic about it. But that may be a bit too... bureaucratic in it's normal form...
How you do it the easy way is to just shove the units through the same mathematical expression you put the numbers through (or do it along with the numbers at the same time).
So mg/L * 1 000 000 * L (I'm going with big "L", easier to see in digital)
with m = 1/1000 and L/L=1 you get
g*1/1000*1 000 000 = g*1000
One thousand grams or 1 kilogram :slight_smile:

 

[CrudeSasquatch]

Easiest way to always be sure is to convert to the base SI units at the start. Then you always get another base SI unit.
How you do it in general is dimensional analysis if you wanna be academic about it. But that may be a bit too... bureaucratic in it's normal form...
How you do it the easy way is to just shove the units through the same mathematical expression you put the numbers through (or do it along with the numbers at the same time).
So mg/L * 1 000 000 * L (I'm going with big "L", easier to see in digital)
with m = 1/1000 and L/L=1 you get
g*1/1000*1 000 000 = g*1000
One thousand grams or 1 kilogram :slight_smile:

Ooh.
Ooh Kay.
So what you're saying is that Canatown, Canaprov, population 0, is actually going to die 100% of the time eh

 

[DarthMatter]

Ooh.
Ooh Kay.
So what you're saying is that Canatown, Canaprov, population 0, is actually going to die 100% of the time eh

Maybe. Did you answer in kilograms?
Are you sure about the numbers?

 

[DarthMatter]

Just take the hole value of what you are calculating and put in the equation (ex you insert 10 kg instead of the number 10) and it should work fine. You will (almost) never gain anything from skipping the units as (almost) everything you calculate has/uses units in some way.

 

[mromutt]

SCIENCE!

 

[DarthMatter]

SCIENCE!

Closer to engineering probably.
If I wanted to go full science I could do the dimensional analysis I mentioned :)

liter = volume = [V]
mg = 10^(-3)kg = 10^(-3) mass = 10^(-3) [M]
Day = time [t]

10^(-3) * [M] * [V]^(-1) * 10^6 * [V] * [t]^(-1) = 10^(-3) * 10^6 * [M] * [t]^(-1)

translated:

=> 10^(-3 + 6)* mass/time
=> 10^3*mass/time

or translated into common terms: kilograms per day

 

[Beerjerker]

Easiest way to always be sure is to convert to the base SI units at the start. Then you always get another base SI unit.
How you do it in general is dimensional analysis if you wanna be academic about it. But that may be a bit too... bureaucratic in it's normal form...
How you do it the easy way is to just shove the units through the same mathematical expression you put the numbers through (or do it along with the numbers at the same time).
So mg/L * 1 000 000 * L (I'm going with big "L", easier to see in digital)
with m = 1/1000 and L/L=1 you get
g*1/1000*1 000 000 = g*1000
One thousand grams or 1 kilogram :slight_smile:

Closer to engineering probably.
If I wanted to go full science I could do the dimensional analysis I mentioned :slight_smile:

liter = volume = [V]
mg = 10^(-3)kg = 10^(-3) mass = 10^(-3) [M]
Day = time [t]

10^(-3) * [M] * [V]^(-1) * 10^6 * [V] * [t]^(-1) = 10^(-3) * 10^6 * [M] * [t]^(-1)

translated:

=> 10^(-3 + 6)* mass/time
=> 10^3*mass/time

or translated into common terms: kilograms per day

 

[mromutt]

View attachment 6308

close enough

 

[DarthMatter]

View attachment 6308

It's so fun to show people outside uni these things. It's completely natural to do this and think in these terms after the first month at my education, so your worldview gets a bit... skewed... since you only hang around those at the same education or the same university :P

 

[Beerjerker]

It's so fun to show people outside uni these things. It's completely natural to do this and think in these terms after the first month at my education, so your worldview gets a bit... skewed... since you only hang around those at the same education or the same university :P

Try not to get corrupted by chaos while you are protecting us from the horrors of the warp!

Maybe that's what happened to @CrudeSasquatch when he poisoned all those fictional people? Should we summon the Inquisition?

 

[Black Sunder]

Try not to get corrupted by chaos while you are protecting us from the horrors of the warp!
View attachment 6309
Maybe that's what happened to @CrudeSasquatch when he poisoned all those fictional people? Should we summon the Inquisition?

Montoya looks different lately.....corporate sponsorship is a bad drug to get hooked on.

 

[DarthMatter]

Try not to get corrupted by chaos while you are protecting us from the horrors of the warp!
View attachment 6309
Maybe that's what happened to @CrudeSasquatch when he poisoned all those fictional people? Should we summon the Inquisition?

No one expects the Emperors inquisition!
Specially not heretics!

 

[mromutt]

No one expects the Emperors inquisition!
Specially not heretics!

some do :P

 

[CrudeSasquatch]

Closer to engineering probably.
If I wanted to go full science I could do the dimensional analysis I mentioned :slight_smile:

liter = volume = [V]
mg = 10^(-3)kg = 10^(-3) mass = 10^(-3) [M]
Day = time [t]

10^(-3) * [M] * [V]^(-1) * 10^6 * [V] * [t]^(-1) = 10^(-3) * 10^6 * [M] * [t]^(-1)

translated:

=> 10^(-3 + 6)* mass/time
=> 10^3*mass/time

or translated into common terms: kilograms per day

So instead of MATH homework I walked toward the subwoofer explosion sounds coming from the practice artillery range and enjoyed the pleasant irresistible percussion of the maths sciences of War. Then I ate hotdogs boiled in tomato ketchup and onion soup, or as the army calls it, "gourmet sausage fiber dinner".

 

[Aramil]

Yeah I've been trying to figure out...
When I times mg/l (or ppm) by MLD (million liters a day) how do I know what the end result is in kg or whatever?
Lol.
Like... I get a number but what's the units in?
Does the 1 by the 1 part per million divided by a million mean I'm in liters now?

Hahaha

What? lol

The answer is obvious! swap the water supply for a beer supply. Who's gonna care after that?

 

[mromutt]

What? lol

The answer is obvious! swap the water supply for a beer supply. Who's gonna care after that?

hey it worked back in the days when it wasnt safe to drink the water, why cant it now? ;)

 

[Dragonslaya54]

You are still not liking shit!
Don't you remember your training?!

My oh my what have I done! I shall create a likening to fix this!

 

[maynard]

...Then I ate hotdogs boiled in tomato ketchup and onion soup, or as the army calls it, "gourmet sausage fiber dinner".

sounds like our school lunch program, where ketchup qualified as a serving of vegetables.